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fix PHP Deprecated: Using ${var} in strings is deprecated, use {$var} instead
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@ -66,13 +66,13 @@ function _check_script_tag(&$var,$name='',$log=true)
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{
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if($log)
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{
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error_log("*** _check_script_tag($name): unset(${name}[$key]) with value '$val'");
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error_log("*** _check_script_tag($name): unset({$name}[$key]) with value '$val'");
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}
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unset($var[$key]);
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}
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elseif($log)
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{
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error_log("*** _check_script_tag($name): HtmlLawed::purify(${name}[$key]) succeeded '$val' --> '{$var[$key]}'");
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error_log("*** _check_script_tag($name): HtmlLawed::purify({$name}[$key]) succeeded '$val' --> '{$var[$key]}'");
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}
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}
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}
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@ -192,4 +192,4 @@ function json_php_unserialize($str, $allow_not_serialized=false)
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return false;
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}
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return $str;
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}
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}
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