added the option allfirst for account display to show [username] firstname lastname, as the option all displayed [username] firstname lastname and not [username] lastname, firstnamne as advertised

This commit is contained in:
Klaus Leithoff 2009-09-28 15:12:08 +00:00
parent 22e7b99927
commit e6d832da22
2 changed files with 5 additions and 1 deletions

View File

@ -381,10 +381,13 @@ class common
case 'lastall': case 'lastall':
$name = $lastname . $delimiter . $firstname . ' ['.$lid.']'; $name = $lastname . $delimiter . $firstname . ' ['.$lid.']';
break; break;
case 'allfirst':
$name = '['.$lid.'] ' . $firstname . ' ' . $lastname;
break;
case 'all': case 'all':
/* fall through */ /* fall through */
default: default:
$name = '['.$lid.'] ' . $firstname . ' ' . $lastname; $name = '['.$lid.'] ' . $lastname . $delimiter . $firstname;
} }
return $name; return $name;
} }

View File

@ -110,6 +110,7 @@
'username' => lang('username'), 'username' => lang('username'),
'firstall' => lang('Firstname').' '.lang('Lastname').' ['.lang('username').']', 'firstall' => lang('Firstname').' '.lang('Lastname').' ['.lang('username').']',
'lastall' => lang('Lastname').', '.lang('Firstname').' ['.lang('username').']', 'lastall' => lang('Lastname').', '.lang('Firstname').' ['.lang('username').']',
'allfirst' => '['.lang('username').'] '.lang('Firstname'). ' '.lang('Lastname'),
'all' => '['.lang('username').'] '.lang('Lastname').', '.lang('Firstname') 'all' => '['.lang('username').'] '.lang('Lastname').', '.lang('Firstname')
); );