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Fix issue with backslashes when using pattern function
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parent
f1c0bbe73c
commit
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@ -1,12 +1,19 @@
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package pattern
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import "path/filepath"
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import (
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"path/filepath"
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"strings"
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)
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// Match checks whether a string matches a pattern
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func Match(pattern, s string) bool {
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if pattern == "*" {
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return true
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}
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// Backslashes break filepath.Match, so we'll remove all of them.
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// This has a pretty significant impact on performance when there
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// are backslashes, but at least it doesn't break filepath.Match.
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s = strings.ReplaceAll(s, "\\", "")
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matched, _ := filepath.Match(pattern, s)
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return matched
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}
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21
pattern/pattern_bench_test.go
Normal file
21
pattern/pattern_bench_test.go
Normal file
@ -0,0 +1,21 @@
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package pattern
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import "testing"
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func BenchmarkMatch(b *testing.B) {
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for n := 0; n < b.N; n++ {
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if !Match("*ing*", "livingroom") {
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b.Error("should've matched")
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}
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}
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b.ReportAllocs()
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}
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func BenchmarkMatchWithBackslash(b *testing.B) {
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for n := 0; n < b.N; n++ {
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if !Match("*ing*", "living\\room") {
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b.Error("should've matched")
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}
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}
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b.ReportAllocs()
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}
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@ -1,6 +1,9 @@
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package pattern
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import "testing"
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import (
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"fmt"
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"testing"
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)
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func TestMatch(t *testing.T) {
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testMatch(t, "*", "livingroom_123", true)
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@ -15,6 +18,7 @@ func TestMatch(t *testing.T) {
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testMatch(t, "*vin*om*2*", "livingroom_123", true)
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testMatch(t, "livingroom_123", "livingroom_123", true)
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testMatch(t, "*livingroom_123*", "livingroom_123", true)
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testMatch(t, "*test*", "\\test", true)
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testMatch(t, "livingroom", "livingroom_123", false)
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testMatch(t, "livingroom123", "livingroom_123", false)
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testMatch(t, "what", "livingroom_123", false)
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@ -24,6 +28,7 @@ func TestMatch(t *testing.T) {
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}
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func testMatch(t *testing.T, pattern, key string, expectedToMatch bool) {
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t.Run(fmt.Sprintf("pattern '%s' from '%s'", pattern, key), func(t *testing.T) {
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matched := Match(pattern, key)
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if expectedToMatch {
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if !matched {
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@ -34,4 +39,5 @@ func testMatch(t *testing.T, pattern, key string, expectedToMatch bool) {
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t.Errorf("%s shouldn't have matched pattern '%s'", key, pattern)
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}
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}
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})
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}
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