- Fix reconnect guard

- Avoid double client creation
This commit is contained in:
Zoltán Papp 2024-06-21 00:55:07 +02:00
parent 6801dcb3f6
commit 06ceac65de
3 changed files with 26 additions and 7 deletions

View File

@ -19,6 +19,10 @@ const (
serverResponseTimeout = 8 * time.Second
)
var (
ErrConnAlreadyExists = fmt.Errorf("connection already exists")
)
// Msg carry the payload from the server to the client. With this sturct, the net.Conn can free the buffer.
type Msg struct {
Payload []byte
@ -157,6 +161,11 @@ func (c *Client) OpenConn(dstPeerID string) (net.Conn, error) {
}
hashedID, hashedStringID := messages.HashID(dstPeerID)
_, ok := c.conns[hashedStringID]
if ok {
return nil, ErrConnAlreadyExists
}
log.Infof("open connection to peer: %s", hashedStringID)
msgChannel := make(chan Msg, 2)
conn := NewConn(c, hashedID, hashedStringID, msgChannel)

View File

@ -26,6 +26,7 @@ func Dial(address string) (net.Conn, error) {
wsConn, _, err := websocket.Dial(context.Background(), url, opts)
if err != nil {
log.Errorf("failed to dial to Relay server '%s': %s", url, err)
return nil, err
}

View File

@ -3,6 +3,8 @@ package client
import (
"context"
"time"
log "github.com/sirupsen/logrus"
)
var (
@ -24,13 +26,20 @@ func NewGuard(context context.Context, relayClient *Client) *Guard {
}
func (g *Guard) OnDisconnected() {
timeout := time.NewTimer(reconnectingTimeout)
defer timeout.Stop()
ticker := time.NewTicker(reconnectingTimeout)
defer ticker.Stop()
for {
select {
case <-timeout.C:
_ = g.relayClient.Connect()
case <-ticker.C:
err := g.relayClient.Connect()
if err != nil {
log.Errorf("failed to reconnect to relay server: %s", err)
continue
}
return
case <-g.ctx.Done():
return
}
}
}