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refactor Value::follow_cell_path
to reduce clones and return Cow
(#15640)
# Description While working on something else, I noticed that `Value::follow_cell_path` receives `self`. While it would be ideal for the signature to be `(&'a self, cell_path) -> &'a Value`, that's not possible because: 1. Selecting a row from a list and field from a record can be done with a reference but selecting a column from a table requires creating a new list. 2. `Value::Custom` returns new `Value`s when indexed. So the signature becomes `(&'a self, cell_path) -> Cow<'a, Value>`. Another complication that arises is, once a new `Value` is created, and it is further indexed, the `current` variable 1. can't be `&'a Value`, as the lifetime requirement means it can't refer to local variables 2. _shouldn't_ be `Cow<'a, Value>`, as once it becomes an owned value, it can't be borrowed ever again, as `current` is derived from its previous value in further iterations. So once it's owned, it can't be indexed by reference, leading to more clones We need `current` to have _two_ possible lifetimes 1. `'out`: references derived from `&self` 2. `'local`: references derived from an owned value stored in a local variable ```rust enum MultiLife<'out, 'local, T> where 'out: 'local, T: ?Sized, { Out(&'out T), Local(&'local T), } ``` With `current: MultiLife<'out, '_, Value>`, we can traverse values with minimal clones, and we can transform it to `Cow<'out, Value>` easily (`MultiLife::Out -> Cow::Borrowed, MultiLife::Local -> Cow::Owned`) to return it # User-Facing Changes # Tests + Formatting # After Submitting --------- Co-authored-by: Bahex <17417311+Bahex@users.noreply.github.com>
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@ -91,8 +91,7 @@ impl Inc {
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pub fn inc(&self, head: Span, value: &Value) -> Result<Value, LabeledError> {
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if let Some(cell_path) = &self.cell_path {
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let working_value = value.clone();
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let cell_value = working_value.follow_cell_path(&cell_path.members, false)?;
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let cell_value = value.follow_cell_path(&cell_path.members, false)?;
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let cell_value = self.inc_value(head, &cell_value)?;
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