rclone/vendor/github.com/aalpar/deheap/deheap.go
2020-03-16 15:50:04 +00:00

229 lines
4.8 KiB
Go

//
// Copyright 2019 Aaron H. Alpar
//
// Permission is hereby granted, free of charge, to any person obtaining
// a copy of this software and associated documentation files
// (the "Software"), to deal in the Software without restriction,
// including without limitation the rights to use, copy, modify, merge,
// publish, distribute, sublicense, and/or sell copies of the Software,
// and to permit persons to whom the Software is furnished to do so,
// subject to the following conditions:
//
// The above copyright notice and this permission notice shall be included
// in all copies or substantial portions of the Software.
//
// THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND,
// EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF
// MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT.
// IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY
// CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION OF CONTRACT,
// TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION WITH THE
// SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.
//
//
// Package deheap provides the implementation of a doubly ended heap.
// Doubly ended heaps are heaps with two sides, a min side and a max side.
// Like normal single-sided heaps, elements can be pushed onto and pulled
// off of a deheap. deheaps have an additional Pop function, PopMax, that
// returns elements from the opposite side of the ordering.
//
// This implementation has emphasized compatibility with existing libraries
// in the sort and heap packages.
//
// Performace of the deheap functions should be very close to the
// performance of the functions of the heap library
//
package deheap
import (
"container/heap"
"math/bits"
)
func hparent(i int) int {
return (i - 1) / 2
}
func hlchild(i int) int {
return (i * 2) + 1
}
func parent(i int) int {
return ((i + 1) / 4) - 1
}
func lchild(i int) int {
return ((i + 1 ) * 4) - 1
}
func level(i int) int {
return bits.Len(uint(i)+1) - 1
}
func isMinHeap(i int) bool {
return level(i) % 2 == 0
}
func min4(h heap.Interface, l int, min bool, i int) int {
q := i
i++
if i >= l {
return q
}
if min == h.Less(i, q) {
q = i
}
i++
if i >= l {
return q
}
if min == h.Less(i, q) {
q = i
}
i++
if i >= l {
return q
}
if min == h.Less(i, q) {
q = i
}
return q
}
// min2
func min2(h heap.Interface, l int, min bool, i int) int {
if i+1 >= l {
return i
}
if min != h.Less(i+1, i) {
return i
}
return i + 1
}
// min3
func min3(h heap.Interface, l int, min bool, i, j, k int) int {
q := i
if j < l && h.Less(j, q) == min {
q = j
}
if k < l && h.Less(k, q) == min {
q = k
}
return q
}
// bubbledown
func bubbledown(h heap.Interface, l int, min bool, i int) (q int, r int) {
q = i
r = i
for {
// find min of children
j := min2(h, l, min, hlchild(i))
if j >= l {
break
}
// find min of grandchildren
k := min4(h, l, min, lchild(i))
// swap of less than the element at i
v := min3(h, l, min, i, j, k)
if v == i || v >= l {
break
}
// v == k
q = v
h.Swap(v, i)
if v == j {
break
}
p := hparent(v)
if h.Less(p, v) == min {
h.Swap(p, v)
r = p
}
i = v
}
return q, r
}
// bubbleup
func bubbleup(h heap.Interface, min bool, i int) (q bool) {
if i < 0 {
return false
}
j := parent(i)
for j >= 0 && min == h.Less(i, j) {
q = true
h.Swap(i, j)
i = j
j = parent(i)
}
min = !min
j = hparent(i)
for j >= 0 && min == h.Less(i, j) {
q = true
h.Swap(i, j)
i = j
j = parent(i)
}
return q
}
// Pop the smallest value off the heap. See heap.Pop().
// Time complexity is O(log n), where n = h.Len()
func Pop(h heap.Interface) interface{} {
l := h.Len()-1
h.Swap(0, l)
q := h.Pop()
bubbledown(h, l, true, 0)
return q
}
// Pop the largest value off the heap. See heap.Pop().
// Time complexity is O(log n), where n = h.Len()
func PopMax(h heap.Interface) interface{} {
l := h.Len()
j := 0
if l > 1 {
j = min2(h, l,false, 1)
}
l = l - 1
h.Swap(j, l)
q := h.Pop()
bubbledown(h, l,false, j)
return q
}
// Remove element at index i. See heap.Remove().
// The complexity is O(log n) where n = h.Len().
func Remove(h heap.Interface, i int) (q interface{}) {
l := h.Len() - 1
h.Swap(i, l)
q = h.Pop()
if l != i {
q, r := bubbledown(h, l, isMinHeap(i), i)
bubbleup(h, isMinHeap(q), q)
bubbleup(h, isMinHeap(r), r)
}
return q
}
// Push an element onto the heap. See heap.Push()
// Time complexity is O(log n), where n = h.Len()
func Push(h heap.Interface, o interface{}) {
h.Push(o)
l := h.Len()
i := l - 1
bubbleup(h, isMinHeap(i), i)
}
// Init initializes the heap.
// This should be called once on non-empty heaps before calling Pop(), PopMax() or Push(). See heap.Init()
func Init(h heap.Interface) {
l := h.Len()
for i := 0; i < l; i++ {
bubbleup(h, isMinHeap(i), i)
}
}