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Delete misleading wording in the explaination of rate limiting
Signed-off-by: Tom Eastep <teastep@shorewall.net>
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@ -1281,9 +1281,9 @@ DNAT net loc:192.168.1.3 tcp 4000:4100</programlisting>
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packets will be logged. After this, it will be 6 seconds (1 minute divided
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packets will be logged. After this, it will be 6 seconds (1 minute divided
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by the rate of 10) before a message will be logged from the rule,
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by the rate of 10) before a message will be logged from the rule,
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regardless of how many packets reach it. Also, every 6 seconds which
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regardless of how many packets reach it. Also, every 6 seconds which
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passes without matching a packet, one of the bursts will be regained; if
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passes, one of the bursts will be regained; if no packets hit the rule for
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no packets hit the rule for 30 seconds, the burst will be fully recharged;
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30 seconds, the burst will be fully recharged; back where we
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back where we started.</para>
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started.</para>
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</section>
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</section>
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<section id="Logical">
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<section id="Logical">
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@ -950,10 +950,10 @@ net all DROP info</programlisting>then the chain name is 'net2all'
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packet will be logged; in fact, since the burst is 5, the first five
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packet will be logged; in fact, since the burst is 5, the first five
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packets will be logged. After this, it will be 6 seconds (1 minute
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packets will be logged. After this, it will be 6 seconds (1 minute
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divided by the rate of 10) before a message will be logged from the
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divided by the rate of 10) before a message will be logged from the
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rule, regardless of how many packets reach it. Also, every 6 seconds
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rule, regardless of how many packets reach it. Also, every 6
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which passes without matching a packet, one of the bursts will be
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seconds, one of the bursts will be regained; if no packets hit the
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regained; if no packets hit the rule for 30 seconds, the burst will
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rule for 30 seconds, the burst will be fully recharged; back where
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be fully recharged; back where we started.</para>
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we started.</para>
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</listitem>
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</listitem>
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</varlistentry>
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</varlistentry>
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@ -827,10 +827,10 @@ net all DROP info</programlisting>then the chain name is 'net2all'
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packet will be logged; in fact, since the burst is 5, the first five
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packet will be logged; in fact, since the burst is 5, the first five
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packets will be logged. After this, it will be 6 seconds (1 minute
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packets will be logged. After this, it will be 6 seconds (1 minute
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divided by the rate of 10) before a message will be logged from the
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divided by the rate of 10) before a message will be logged from the
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rule, regardless of how many packets reach it. Also, every 6 seconds
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rule, regardless of how many packets reach it. Also, every 6
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which passes without matching a packet, one of the bursts will be
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seconds, one of the bursts will be regained; if no packets hit the
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regained; if no packets hit the rule for 30 seconds, the burst will
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rule for 30 seconds, the burst will be fully recharged; back where
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be fully recharged; back where we started.</para>
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we started.</para>
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</listitem>
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</listitem>
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</varlistentry>
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</varlistentry>
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