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Incorporated proposal by @JeLuF in #1324
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@ -1342,6 +1342,16 @@ function getPromptsNumber(prompts) {
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prompts = prompts.map((prompt) => prompt.trim())
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prompts = prompts.filter((prompt) => prompt !== "")
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// estimate number of prompts
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let estimatedNumberOfPrompts = 0
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prompts.forEach((prompt) => {
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estimatedNumberOfPrompts += (prompt.match(/{[^}]*}/g) || []).map((e) => e.match(/,/g).length + 1).reduce( (p,a) => p*a, 1) * (2**(prompt.match(/\|/g) || []).length)
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})
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if (estimatedNumberOfPrompts >= 10000) {
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return 10000
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}
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promptsToMake = applySetOperator(prompts) // switched those around as Set grows in a linear fashion and permute in 2^n, and one has to be computed for the other to be calculated
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numberOfPrompts = applyPermuteOperatorNumber(promptsToMake)
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}
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@ -1613,9 +1623,15 @@ function renameMakeImageButton() {
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imageLabel = totalImages + " Images"
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}
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if (SD.activeTasks.size == 0) {
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makeImageBtn.innerText = "Make " + imageLabel
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if (totalImages >= 10000)
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makeImageBtn.innerText = "Make tens of thousands of images"
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else
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makeImageBtn.innerText = "Make " + imageLabel
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} else {
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makeImageBtn.innerText = "Enqueue Next " + imageLabel
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if (totalImages >= 10000)
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makeImageBtn.innerText = "Enqueue tens of thousands of images"
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else
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makeImageBtn.innerText = "Enqueue Next " + imageLabel
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}
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}
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numOutputsTotalField.addEventListener("change", renameMakeImageButton)
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